2054:【例3.4】适合晨练-信息学奥赛一本通
2023-04-23 08:15:00 来源:哔哩哔哩
#include<algorithm>
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#include<cmath>
#include<cstdio>
#include<iostream>
using namespace std;
int main(){
int t;
cin>>t;
if(25<=t and t<=30){
cout<<"ok!";
}
else{
cout<<"no!";
}
return 0;
}
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